let’s say a marble that weighed 0.006 kg was on a 1 m tall ramp. It went down the ramp at a velocity of 4.4 (m/s) and went through a loop with a height of 0.25 m. The marbles ending velocity as it was at the end of the loop and end of the ramp was at a velocity of 1.7 (m/s). Calculate the amount of potential energy at the top of the loop.

1 answer

To calculate the potential energy at the top of the loop, we first need to find the height above the ground at that point. Since the marble went through a loop with a height of 0.25 m, the height above the ground at the top of the loop is also 0.25 m.

The potential energy (PE) is given by the equation:

PE = m * g * h

where m is the mass of the marble, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height above the ground.

Given:
Mass of marble (m) = 0.006 kg
Height above the ground (h) = 0.25 m
Acceleration due to gravity (g) = 9.8 m/s²

PE = 0.006 kg * 9.8 m/s² * 0.25 m
= 0.0147 Joules (J)

Therefore, the potential energy at the top of the loop is approximately 0.0147 Joules.