Question
what is the fibonacci sequence and what is its relationship to the golden ratio?
http://www.google.com/search?q=fibonacci+golden+ratio&start=0&ie=utf-8&oe=utf-8&client=firefox-a&rls=org.mozilla:en-US:official
Many websites here that can help you -- especially the very first one from mathforum.org.
=)
The Fibonacci sequence begins
1,1,2,3,5,8,13,...
Each term after the second 1 is the sum of the previous two terms.
The golden number (or ratio) is (1+sqrt(5))/2 and is approxximately 1.6180339
The relationship of the Fibonacci sequence to the golden number is that if you take the ratio of the n-th term/(n-1)th term as n increases the limit of the ratio is the golden number. Thus in the sequence given above, consider the sequence of terms
2/1, 3/2, 5/3, 8/5, 13/8,...
That sequence of ratios of Fib. terms converges to the golden number. The last term , 13/8, is approx 1.625 Each term after that gets closer and closer to the gold. ratio.
i can't finish this h.w . because i can't find the factorzation for 293 and the h.w is due tomorrow!
293 is prime
test the divisor 2,3,5,7,11,13 and 17 to prove this.
Please post new questions or we'll miss your post.
http://www.google.com/search?q=fibonacci+golden+ratio&start=0&ie=utf-8&oe=utf-8&client=firefox-a&rls=org.mozilla:en-US:official
Many websites here that can help you -- especially the very first one from mathforum.org.
=)
The Fibonacci sequence begins
1,1,2,3,5,8,13,...
Each term after the second 1 is the sum of the previous two terms.
The golden number (or ratio) is (1+sqrt(5))/2 and is approxximately 1.6180339
The relationship of the Fibonacci sequence to the golden number is that if you take the ratio of the n-th term/(n-1)th term as n increases the limit of the ratio is the golden number. Thus in the sequence given above, consider the sequence of terms
2/1, 3/2, 5/3, 8/5, 13/8,...
That sequence of ratios of Fib. terms converges to the golden number. The last term , 13/8, is approx 1.625 Each term after that gets closer and closer to the gold. ratio.
i can't finish this h.w . because i can't find the factorzation for 293 and the h.w is due tomorrow!
293 is prime
test the divisor 2,3,5,7,11,13 and 17 to prove this.
Please post new questions or we'll miss your post.
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