there is no air resistance.

using a cannonball launcher, how can i find how far the cannonball will go (horizontally) if launched at 30 degrees?

heres what i know:

-the vertical displacement is -.245m
-the vertical acceleration is -9.81m/s^2
-at 0 degrees, the initial velocity is 4.52 m/s

(answer should be around 1-5m)
THANKS SO MUCH IN ADVANCE

3 answers

Without air resistance, you can treat the vertical and horizontal motions separately.
Resolve the muzzle velocity um=4.52 m/s into its horizontal and vertical components, ux and uy using
ux=um cos(30)
uy=um sin(30)

From the vertical displacement S=-245m, acceleration of -9.81 m/s/s, you can calculate the time required using
S = uy t + (1/2)(-9.81)t²
Reject the negative solution of t.

The horizontal distance is ux*t.

thanks a ton! =)

You're welcome!