Select ALL equivalent expressions to:
(7𝑥 ― 2) ― (0.04𝑥 ― 3 + 0.2𝑥)
(2 points)
Responses
(7x −
2) −
(0.24x −
3)
(7x negative 2) negative (0.24x negative 3)
7.16x −
5
7.16x negative5
6.76x +
1
6.76x plus 1
5.76x
5.76x
7.76x
9 answers
5.76x
choose two
The two equivalent expressions are:
(7x - 2) - (0.24x - 3)
5.76x
(7x - 2) - (0.24x - 3)
5.76x
Jill is thinking of a number. Four more than three times the number is thirteen. What is the number?(1 point)
Jill's number is
Jill's number is
Jill's number is 3.
What is the value of 𝑦 in the equation below?
6(𝑦 ― 1.5) = 30
(1 point)
Responses
181.5
181.5
6.5
6.5
4.75
4.75
3.5
3.5
6(𝑦 ― 1.5) = 30
(1 point)
Responses
181.5
181.5
6.5
6.5
4.75
4.75
3.5
3.5
To find the value of 𝑦, we need to solve the given equation:
6(𝑦 - 1.5) = 30
Expanding, we have:
6𝑦 - 9 = 30
Adding 9 to both sides:
6𝑦 = 39
Dividing both sides by 6:
𝑦 = 39/6
Simplifying the fraction, we have:
𝑦 = 6.5
Therefore, the value of 𝑦 in the equation is 6.5.
6(𝑦 - 1.5) = 30
Expanding, we have:
6𝑦 - 9 = 30
Adding 9 to both sides:
6𝑦 = 39
Dividing both sides by 6:
𝑦 = 39/6
Simplifying the fraction, we have:
𝑦 = 6.5
Therefore, the value of 𝑦 in the equation is 6.5.
To rent a car you need to pay a flat fee plus $0.20 for each mile that you drive. Which equation could be used to solve for the price of the initial fee if the total cost of a rental was $60 when the car was driven 40 miles?(2 points)
Responses
60 + 0.2(40) = x
60 + 0.2(40) = x
0.2x + 40 = 60
0.2x + 40 = 60
0.2(60) + x = 40
0.2(60) + x = 40
x + 0.2(40) = 60
Responses
60 + 0.2(40) = x
60 + 0.2(40) = x
0.2x + 40 = 60
0.2x + 40 = 60
0.2(60) + x = 40
0.2(60) + x = 40
x + 0.2(40) = 60
To solve for the price of the initial fee, we can use the equation:
x + 0.2(40) = 60
where x represents the price of the initial fee.
The equation states that the initial fee, represented by x, plus $0.20 for each mile driven (0.20(40)), should total $60.
x + 0.2(40) = 60
where x represents the price of the initial fee.
The equation states that the initial fee, represented by x, plus $0.20 for each mile driven (0.20(40)), should total $60.