Sue is wrapping books to give as gifts Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inchesBased on surface area, which book will require less wrapping paper? (1 point)

Answer 1

To calculate the surface area, we need to find the sum of the areas of all the faces of each book.

For Book A:
- The area of the front and back faces is 6.5 inches * 8.5 inches = 55.25 square inches
- The area of the two side faces is 1 inch * 8.5 inches + 1 inch * 8.5 inches = 17 square inches
- The area of the top and bottom faces is 6.5 inches * 1 inch + 6.5 inches * 1 inch = 13 square inches
The total surface area of Book A is 55.25 + 17 + 13 = 85.25 square inches.

For Book B:
- The area of the front and back faces is 5.5 inches * 8 inches = 44 square inches
- The area of the two side faces is 2 inches * 8 inches + 2 inches * 8 inches = 32 square inches
- The area of the top and bottom faces is 5.5 inches * 2 inches + 5.5 inches * 2 inches = 22 square inches
The total surface area of Book B is 44 + 32 + 22 = 98 square inches.

Therefore, Book A will require less wrapping paper.