Asked by maelee
Gamblers are playing a game of chance in which they have a 1/40 chance of winning $90. What is the expected payout of this game?
x 0 90
p(x)
x.p(x)
x 0 90
p(x)
x.p(x)
Answers
Answered by
bobpursley
P(x)=1/40
xP(x)=90/40
xP(x)=90/40
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