Asked by Reiny
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
rather silly question, and some of it makes no sense
eg look at the first part
......-2(4-5)<b>2</b>-1
does this end up -2(-1)(2) ? or did you forget an operator before the last 2?
there is a similar discrepancy near the end of the mess.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
rather silly question, and some of it makes no sense
eg look at the first part
......-2(4-5)<b>2</b>-1
does this end up -2(-1)(2) ? or did you forget an operator before the last 2?
there is a similar discrepancy near the end of the mess.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
Answers
Answered by
PsyDAG
First, get rid of the parentheses within the parentheses by combining those terms. I will assume a plus sign in front of the third 2 and the last 1.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
3(2+3+1+2-1)-3(2+8-8-9+1-2+1-3)+4-5
Next combine terms within the parentheses, multiply and then add the products.
I hope this helps. Thanks for asking.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
3(2+3+1+2-1)-3(2+8-8-9+1-2+1-3)+4-5
Next combine terms within the parentheses, multiply and then add the products.
I hope this helps. Thanks for asking.
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