The Law of Conservation of Mass states that mass is neither created nor destroyed in a chemical reaction. Therefore, the total mass of the reactants should be equal to the total mass of the products.
Given that 88 g of carbon dioxide is produced in the reaction and 24 g of carbon is one of the reactants, we can start by finding the mass of oxygen in the carbon dioxide.
The molar mass of carbon dioxide is 44 g/mol, and since we have 88 g of carbon dioxide, we can calculate the number of moles of carbon dioxide:
88 g CO2 * (1 mol CO2 / 44 g CO2) = 2 mol CO2
Since there is 1 mol of carbon in each mol of carbon dioxide, we can conclude that there are 2 mol of carbon in the reaction.
Now, we can subtract the mass of carbon from the total mass of the reactants to find the mass of oxygen:
Total mass of reactants = 24 g (carbon) + X (oxygen)
Total mass of reactants = 2 mol (carbon) * 12 g/mol (molar mass of carbon) + X mol (oxygen) * 16 g/mol (molar mass of oxygen)
Since the total mass of the reactants is conserved, we can equate the two expressions:
24 g + X = 24 g + 2(12 g) + X(16 g/mol)
Simplifying the equation:
24 g + X = 24 g + 24 g + 16X g
X = 24 g
Therefore, the mass of dioxygen in the reactants is 24 g.
According to the Law of Conservation of Mass, if 88 g of carbon dioxide (CO2
C
O
2
) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen (O2
O
2
) in the reactants?(1 point)
Responses
64 g
64 g
104 g
104 g
24 g
24 g
32 g
1 answer