To solve a 3D triangle with a known base and slanted faces, you can use the Pythagorean theorem and some basic trigonometry.
1. Start by drawing a sketch of the 3D triangle. Label the base as "b" with a length of 168 units. Label the height as "h" (which is perpendicular to the base).
2. Use the Pythagorean theorem to find the height "h". The Pythagorean theorem states that the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. In this case, the hypotenuse is one of the slanted faces, which has a length of 10.6 units, and one leg is the height "h". The other leg is the distance from the vertex of the triangle to the midpoint of the base, which is half of the base length (168/2 = 84 units).
Using the Pythagorean theorem, we have:
h^2 + 84^2 = 10.6^2
h^2 + 7056 = 112.36
h^2 = 112.36 - 7056
h^2 = -6943.64
Since h^2 is negative, it means that the triangle does not exist.
Please double-check the given values for the slanted faces as it seems there may be a mistake in the measurements.
how to solve a 3d triangle with a base of 168 and slanted faces of 10 and 10.6
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