See:
http://img40.imageshack.us/i/asdasdye.jpg/
h t t p : / / i m g 4 0 . i m a g e s h a c k . u s / c o n t e n t . p h p ? p a g e = d o n e& l = i m g 4 0 / 1 4 8 / a s d a s d y e . j p g & v i a = m u p l o a d
(def of tan theta = a^-1 o)a = o
opposite = adjacent tan theta
written with respect to the first angle
opposite = (adjacent 1 + adjacent 2) tan theta one
were adjacent 1 is the 50 feet
written for the second angle
opposite = adjacent 2 tan theta two
set them equal to each other
(adjacent 1 + adjacent 2) tan theta one = adjacent 2 tan theta two
distripute
adjacent 1 tan theta one + adjacent 2 tan theta one = adjacent 2 tan theta two
subtract from both sides
adjacent 1 tan theta one = adjacent 2 tan theta two - adjacent 2 tan theta one
factor or whatever
adjacent 1 tan theta one = adjacent 2 (tan theta two - tan theta one)
muliply by inverse to solve for adjacent 2
(adjacent 1 tan theta one = adjacent 2 (tan theta two - tan theta one)) ((tan theta two - tan theta one)^-1
adjacent two = (tan theta two - tan theta one)^-1 adjacent 1 tan theta one
plug and chug for adjacent two
adjacent two = (tan 32 degrees - tan 40 degrees)^-1 (50 ft) tan theta 40 degrees
I got negative 195.8 feet?
6 answers
that would be the image i put up...
i don\'t understand???
i don\'t understand???
If you look at the figure, you will see that θ1 should be smaller than θ2, but you have labelled θ1=40, and θ2=32.
Perhaps the two values have been inverted and perhaps that is the source of your problem.
Could you please check and let us know?
Perhaps the two values have been inverted and perhaps that is the source of your problem.
Could you please check and let us know?
Yes, I translated the link so that other people could see your image without having to go through the hassle I had to.
hmmmm ok i\'ll try and see what i get thanks
high school Goraul vaishali