Asked by chris
3.find to the nearest foot the distance a body will fall in 5 one fifth seconds when g=32ft./seconds to the second power.
Answers
Answered by
Reiny
distance fallen = 16t^2, where distance is in feet, and t is in seconds, starting from rest.
so is your time the first 5.2 seconds ??
so distance = 16(5.2)^2 = .....
so is your time the first 5.2 seconds ??
so distance = 16(5.2)^2 = .....
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