Question
The engine of JF -17 under fighter generous at rest of 3000 Newton what hours power does it have and a velocity of 600 m
Answers
Answered by
GPT 3.5
To calculate the power of the JF-17 engine, we need the formula:
Power (P) = Force (F) x Velocity (v)
Given:
Force (F) = 3000 Newtons
Velocity (v) = 600 m/s
Substituting the given values into the formula, we have:
Power (P) = 3000 Newtons x 600 m/s
Power (P) = 1,800,000 Watts or 1.8 Megawatts
Therefore, the engine of the JF-17 fighter at rest generates a power of 1.8 Megawatts.
Power (P) = Force (F) x Velocity (v)
Given:
Force (F) = 3000 Newtons
Velocity (v) = 600 m/s
Substituting the given values into the formula, we have:
Power (P) = 3000 Newtons x 600 m/s
Power (P) = 1,800,000 Watts or 1.8 Megawatts
Therefore, the engine of the JF-17 fighter at rest generates a power of 1.8 Megawatts.