To find the surface area of a rectangular pyramid, we need to find the area of the base and add the areas of the four triangular faces.
The area of the base is given by $lw=8\text{ cm}\cdot 4\text{ cm}=32\text{ cm}^2$.
The area of each triangular face is given by $(1/2)(lw)=\tfrac12(8\text{ cm})(2\text{ cm})=8\text{ cm}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 8\text{ cm}^2=32\text{ cm}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $32\text{ cm}^2+32\text{ cm}^2=\boxed{64\text{ cm}^2}$.
Find the surface area of a rectangular pyramid with these measurements: l = 8 cm, w = 4 cm, and h = 2 cm. Express your answer as a decimal rounded to the nearest hundredth. .
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What
if r = 8 m, w = 4 m, and h = 2 m. Express your answer as a mixed number.
The surface area of a rectangular pyramid is calculated by finding the area of the base and adding the areas of the four triangular faces.
The area of the base is given by $lw=8\text{ m}\cdot 4\text{ m}=32\text{ m}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(8\text{ m})(2\text{ m})=8\text{ m}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 8\text{ m}^2=32\text{ m}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $32\text{ m}^2+32\text{ m}^2=\boxed{64\text{ m}^2}$.
The surface area of a rectangular pyramid is calculated by finding the area of the base and adding the areas of the four triangular faces.
The area of the base is given by $lw=8\text{ m}\cdot 4\text{ m}=32\text{ m}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(8\text{ m})(2\text{ m})=8\text{ m}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 8\text{ m}^2=32\text{ m}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $32\text{ m}^2+32\text{ m}^2=\boxed{64\text{ m}^2}$.
Find the surface area of a rectangular pyramid with these measurements: l = 8 cm, w = 4 cm, and h = 2 cm. Express your answer as a decimal rounded to the nearest hundredth.
To find the surface area of a rectangular pyramid, we need to find the area of the base and add the areas of the four triangular faces.
The area of the base is given by $lw=8\text{ cm}\cdot 4\text{ cm}=32\text{ cm}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(8\text{ cm})(2\text{ cm})=8\text{ cm}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 8\text{ cm}^2=32\text{ cm}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $32\text{ cm}^2+32\text{ cm}^2=64\text{ cm}^2$.
Rounding to the nearest hundredth, the surface area of the pyramid is $\boxed{64.00\text{ cm}^2}$.
The area of the base is given by $lw=8\text{ cm}\cdot 4\text{ cm}=32\text{ cm}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(8\text{ cm})(2\text{ cm})=8\text{ cm}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 8\text{ cm}^2=32\text{ cm}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $32\text{ cm}^2+32\text{ cm}^2=64\text{ cm}^2$.
Rounding to the nearest hundredth, the surface area of the pyramid is $\boxed{64.00\text{ cm}^2}$.
Find the surface area of a rectangular pyramid with these measurements: l= 13 cm, w= 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.
To find the surface area of a rectangular pyramid, we need to find the area of the base and add the areas of the four triangular faces.
The area of the base is given by $lw=13\text{ cm}\cdot 11\text{ cm}=143\text{ cm}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(13\text{ cm})(8\text{ cm})=52\text{ cm}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 52\text{ cm}^2=208\text{ cm}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $143\text{ cm}^2+208\text{ cm}^2=351\text{ cm}^2$.
Rounding to the nearest hundredth, the surface area of the pyramid is $\boxed{351.00\text{ cm}^2}$.
The area of the base is given by $lw=13\text{ cm}\cdot 11\text{ cm}=143\text{ cm}^2$.
The area of each triangular face is given by $\frac{1}{2}(lw)=\frac{1}{2}(13\text{ cm})(8\text{ cm})=52\text{ cm}^2$. There are four triangular faces, so the total area of the triangular faces is $4\cdot 52\text{ cm}^2=208\text{ cm}^2$.
The total surface area is the sum of the areas of the base and triangular faces, which is $143\text{ cm}^2+208\text{ cm}^2=351\text{ cm}^2$.
Rounding to the nearest hundredth, the surface area of the pyramid is $\boxed{351.00\text{ cm}^2}$.
11 answers