Asked by Shawn - tricky question
                1/3x > 2 and 1/4x > 2 
both are less than one so how do i graph this on the number line?
I'm confused.
I will assume you meant (1/3)x>2 and not 1/(3x)>2
With that assumption, you would get x>6 AND x>8
x>6 is a line to the right of 6, excluding the 6
x>8 is a line to the right of 8, excluding the 8
So the intersection, or all elements that belong to BOTH, would be all those to the right of 8, exluding the 8, since 8 satisfies the first but not the second
so draw on open circle around the 8 then a line to the right of it, with an arrow at its end
            
        both are less than one so how do i graph this on the number line?
I'm confused.
I will assume you meant (1/3)x>2 and not 1/(3x)>2
With that assumption, you would get x>6 AND x>8
x>6 is a line to the right of 6, excluding the 6
x>8 is a line to the right of 8, excluding the 8
So the intersection, or all elements that belong to BOTH, would be all those to the right of 8, exluding the 8, since 8 satisfies the first but not the second
so draw on open circle around the 8 then a line to the right of it, with an arrow at its end
Answers
                    Answered by
            Anonymous
            
    How do you graph 1/4x-5
    
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