Solve for x and graph the solution on the number line below.

Question

−7≥−3x+8and
−3x+8>−19

Answer 1

To solve the first inequality, we need to isolate x. We can start by subtracting 8 from both sides:

-7 - 8 ≥ -3x
-15 ≥ -3x

Next, we can divide both sides by -3. However, we need to remember that whenever we multiply or divide by a negative number, we need to reverse the inequality sign:

-15/-3 ≤ -3x/-3
5 ≥ x

The solution for the first inequality is x ≤ 5.

Now let's solve the second inequality. We can start by subtracting 8 from both sides:

-3x + 8 - 8 > -19 - 8
-3x > -27

Next, divide both sides by -3, remembering to reverse the inequality sign:

-3x / -3 < -27 / -3
x < 9

The solution for the second inequality is x < 9.

Now we can graph the solutions on a number line:

<-----O---------O---------->
5 9

The interval that satisfies both inequalities is x ≤ 5.

Answer 2

pls put the number line right

Answer 3

Here is the corrected number line:

<-----O--------O---------->
5 9

The interval that satisfies both inequalities is x ≤ 5.

Answer 4

is it 5,9?

Answer 5

My apologies for the mistake. The correct number line would be:

<------o----------------------------o------->
5 9

The intervals that satisfy both inequalities are x ≤ 5 and x < 9.