To find the value of a, we can set up the following equation:
8 x 10^3 = 40(a x 10^2)
We can simplify the equation by canceling out the common factor of 10^2 on both sides:
8 x 10^(3-2) = 40a
8 x 10^1 = 40a
80 = 40a
Now, we can divide both sides of the equation by 40 to solve for a:
80/40 = a
2 = a
Therefore, the value of a is 2.
For what value of a will 8 x 10^3 be forty times larger than a x 10^2?
1 answer