The given equation is in the form of a quadratic function, y = ax^2 + bx + c. The vertex of a quadratic function in this form can be found using the formula x = -b/2a.
In this case, a = 3 and b = 72.
Using the formula, x = -72/(2*3) = -72/6 = -12.
Substituting x = -12 into the given equation, we find y = 3(-12 + 12)^2 - 7 = 3(0)^2 - 7 = -7.
Therefore, the vertex of the quadratic function y = 3(x + 12)^2 - 7 is (-12, -7).
Identify the vertex of `y=3\left(x+12\right)^{2}-7`
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