To find the equation of a line parallel to the given equation (y = -1/4 x + 5) that passes through the given point (-8,6), we can use the point-slope form of a linear equation. The equation will have the form:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope of the given equation.
The slope of the given equation is -1/4, so we have:
y - 6 = -1/4(x - (-8))
Simplifying, we get:
y - 6 = -1/4(x + 8)
Now we can distribute the -1/4 to both terms in the parentheses:
y - 6 = -1/4x - 2
Finally, adding 6 to both sides to isolate the y-term, we get:
y = -1/4x - 2 + 6
Simplifying further, we get:
y = -1/4x + 4
Therefore, the equation of the line parallel to the given equation and passing through the point (-8,6) is:
y = -1/4x + 4.
13. Write the equation of the line that passes through the given point and is parallel to the graph of the given equation: ((-8,6); y = -1/4 x + 5
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1 point
y = 4/1 x + 5
y = 3/2 - 20
y = -1/4x + 4
y = 1/4 x - 4
1 answer