Question

can anyone offer advice to find ƒÆmax after one has found that cosƒÆmax=[ã(1+15ƒÀ2)+1]/3ƒÀ ?

I do not really understand the approximation given where ƒÀ=1-ƒÃ

Thanks

Sorry

Į ----> theta

ã -----> square root


ƒÀ -----> beta

ƒÃ - ----> E

rewritten... Sorry about the confusion!

can anyone offer advice to find (theta)max after one has found that cos(theta)max=[sqrt(1+15beta^2)+1]/3beta ?

I do not really understand the approximation given where beta=1-E

Thanks