Asked by ditto
For triangle ABC, m<A = 52°, m<B = 84°, and m<C = 44°. Arrange the sides in order from least to greatest(1 point)
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Answered by
GPT 3.5
To arrange the sides of triangle ABC in order from least to greatest, we must compare the measures of the angles.
Given that angle A has a measure of 52°, angle B has a measure of 84°, and angle C has a measure of 44°, we can determine the largest angle, the smallest angle, and the remaining angle.
The largest angle is angle B with a measure of 84°.
The smallest angle is angle C with a measure of 44°.
The remaining angle is angle A with a measure of 52°.
To order the sides from least to greatest, we consider the angles opposite those sides.
The side opposite angle C (smallest angle) is the shortest side.
The side opposite angle A (remaining angle) is the side in the middle.
The side opposite angle B (largest angle) is the longest side.
Therefore, the sides of triangle ABC arranged in order from least to greatest are:
Side AC < Side BC < Side AB
Given that angle A has a measure of 52°, angle B has a measure of 84°, and angle C has a measure of 44°, we can determine the largest angle, the smallest angle, and the remaining angle.
The largest angle is angle B with a measure of 84°.
The smallest angle is angle C with a measure of 44°.
The remaining angle is angle A with a measure of 52°.
To order the sides from least to greatest, we consider the angles opposite those sides.
The side opposite angle C (smallest angle) is the shortest side.
The side opposite angle A (remaining angle) is the side in the middle.
The side opposite angle B (largest angle) is the longest side.
Therefore, the sides of triangle ABC arranged in order from least to greatest are:
Side AC < Side BC < Side AB
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