Question

Which linear function equation below would contain the points -6 -8, and 12 and four

Answer 1

To find the equation of a linear function, we need two points on the line.

We are given two points (-6, -8) and (12, 4).

First, let's find the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Using the points (-6, -8) and (12, 4), we get:

m = (4 - (-8)) / (12 - (-6))
= (4 + 8) / (12 + 6)
= 12 / 18
= 2 / 3

Now that we have the slope (m), we can use the point-slope form to find the equation of the line. The point-slope form is given by:

y - y1 = m(x - x1)

Plugging in the values from one of the points (-6, -8) into the point-slope form, we get:

y - (-8) = (2/3)(x - (-6))
y + 8 = (2/3)(x + 6)

Rearranging the equation, we get:

y + 8 = (2/3)x + 4

Next, we can simplify the equation by subtracting 8 from both sides:

y = (2/3)x + 4 - 8
y = (2/3)x - 4

Therefore, the linear function equation that contains the points (-6, -8) and (12, 4) is y = (2/3)x - 4.