To solve the quadratic equation 4x^2 + 2x = 10, we can begin by rearranging the equation to the form ax^2 + bx + c = 0. In this case, we have 4x^2 + 2x - 10 = 0.
Next, we can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions can be found using the formula: x = (-b ± √(b^2 - 4ac)) / (2a).
Applying this formula to our equation 4x^2 + 2x - 10 = 0, we have:
x = (-2 ± √(2^2 - 4 * 4 * -10)) / (2 * 4)
x = (-2 ± √(4 + 160)) / 8
x = (-2 ± √164) / 8
To find the solutions rounded to the nearest hundredth, we need to compute the values of (-2 + √164) / 8 and (-2 - √164) / 8.
Using a calculator or computational tool, we find that:
(-2 + √164) / 8 ≈ 0.83
(-2 - √164) / 8 ≈ -1.83
Therefore, the solutions rounded to the nearest hundredth are approximately:
x ≈ 0.83
x ≈ -1.83
Answer: the solutions to the quadratic equation 4x^2 + 2x = 10 (rounded to the nearest hundredth) are approximately 0.83 and -1.83.
Which of the following is a solution to the quadratic equation 4x2+2x=10%0D%0A4%0D%0A%0D%0A2%0D%0A+%0D%0A2%0D%0A%0D%0A=%0D%0A10%0D%0A ? Assume that the solution has been rounded to the nearest hundredth, if applicable.
1 answer