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The distance between the school and the library is 312 miles. The distance between the library and Town Hall is 114 miles. How...Asked by Can't see all
The distance between the school and the library is 3 1/2 miles. The distance between the library and Town Hall is 1 1/4 miles. How many miles farther is it from the school to the library than from the library to Town Hall?(1 point)
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Answered by
Can't see all
Maisie cuts 7 4/5 inches from a ribbon that is 10 1/5 inches long. How many inches remain on the ribbon?(1 point)
Answered by
Can't see all
To make soup, Philip mixes 3 3/8 cups of broth with 2 1/4 cups of water. How many cups of liquid does he use?(1 point)
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GPT 3.5
To find the difference, we need to subtract the distance from the library to Town Hall from the distance from the school to the library.
Distance from school to library = 3 1/2 miles
Distance from library to Town Hall = 1 1/4 miles
Difference = 3 1/2 miles - 1 1/4 miles
= 14/4 - 5/4
= 9/4
= 2 1/4 miles
The school is 2 1/4 miles farther from the library than from the library to Town Hall. Answer: \boxed{2 \frac{1}{4}} miles.
Distance from school to library = 3 1/2 miles
Distance from library to Town Hall = 1 1/4 miles
Difference = 3 1/2 miles - 1 1/4 miles
= 14/4 - 5/4
= 9/4
= 2 1/4 miles
The school is 2 1/4 miles farther from the library than from the library to Town Hall. Answer: \boxed{2 \frac{1}{4}} miles.
Answered by
GPT 3.5
To find the remaining inches on the ribbon, we need to subtract the inches cut from the total length of the ribbon.
Total length of the ribbon = 10 1/5 inches
Inches cut = 7 4/5 inches
To subtract mixed numbers, we need to first convert them to improper fractions.
Total length of the ribbon = 10 + 1/5 = 51/5 inches
Inches cut = 7 + 4/5 = 39/5 inches
Remaining inches = Total length of the ribbon - Inches cut
= 51/5 - 39/5
= (51 - 39)/5
= 12/5
= 2 2/5 inches
Therefore, 2 2/5 inches remain on the ribbon. Answer: \boxed{2 \frac{2}{5}} inches
Total length of the ribbon = 10 1/5 inches
Inches cut = 7 4/5 inches
To subtract mixed numbers, we need to first convert them to improper fractions.
Total length of the ribbon = 10 + 1/5 = 51/5 inches
Inches cut = 7 + 4/5 = 39/5 inches
Remaining inches = Total length of the ribbon - Inches cut
= 51/5 - 39/5
= (51 - 39)/5
= 12/5
= 2 2/5 inches
Therefore, 2 2/5 inches remain on the ribbon. Answer: \boxed{2 \frac{2}{5}} inches
Answered by
GPT 3.5
To find the total cups of liquid Philip uses, we need to add the cups of broth to the cups of water.
Cups of broth = 3 3/8 cups
Cups of water = 2 1/4 cups
To add mixed numbers, we need to first convert them to improper fractions.
Cups of broth = 3 + 3/8 = 27/8 cups
Cups of water = 2 + 1/4 = 9/4 cups
Total cups of liquid = Cups of broth + Cups of water
= 27/8 + 9/4
To add fractions with different denominators, we need to find a common denominator.
The least common multiple of 8 and 4 is 8.
Total cups of liquid = (27/8)(2/2) + (9/4)(2/2)
= (54/16) + (18/8)
= 54/16 + 36/16
= 90/16
= 5 10/16
We can simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
Total cups of liquid = (5/2)(1/8)
= 5/2
= 2 1/2 cups
Therefore, Philip uses 2 1/2 cups of liquid. Answer: \boxed{2 \frac{1}{2}} \text{ cups}.
Cups of broth = 3 3/8 cups
Cups of water = 2 1/4 cups
To add mixed numbers, we need to first convert them to improper fractions.
Cups of broth = 3 + 3/8 = 27/8 cups
Cups of water = 2 + 1/4 = 9/4 cups
Total cups of liquid = Cups of broth + Cups of water
= 27/8 + 9/4
To add fractions with different denominators, we need to find a common denominator.
The least common multiple of 8 and 4 is 8.
Total cups of liquid = (27/8)(2/2) + (9/4)(2/2)
= (54/16) + (18/8)
= 54/16 + 36/16
= 90/16
= 5 10/16
We can simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
Total cups of liquid = (5/2)(1/8)
= 5/2
= 2 1/2 cups
Therefore, Philip uses 2 1/2 cups of liquid. Answer: \boxed{2 \frac{1}{2}} \text{ cups}.
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