A cyclist leaves his training base for a morning workout, riding at the rate of 18 mph. One hour later, his support staff leaves the base in a car going 45 mph in the same direction. How long will it take the support staff to catch up with the cyclist?

Question

A cyclist leaves his training base for a morning workout, riding at the rate of 18 mph.  One hour later, his support staff leaves the base in a car going 45 mph in the same direction.  How long will it take the support staff to catch up with the cyclist?

bobpursley · Answer

same distance, 3/4 hr difference. d=18t d=45(t-3/4) set them equal, solve for t, the total time the cyclist biked. Then, solve for t-3/4

Anonymous · Answer

2/3