Asked by Michelle
What is the molarity of a solution in which 13.7 g of calcium chloride is dissolved in water to a final volume of 750.0 mL?
Answers
Answered by
MathMate
Atomic weight of
Ca : 40
Cl : 35.5
Molecular weight of CaCl2=40+35.5*2=111
Moles=weight in grams/Molecular weight
=13.7/111 = 0.1234 moles
Molarity = 0.1234 moles/750 ml.
=0.165 moles/l
Please check the atomic weights and the calculations.
Ca : 40
Cl : 35.5
Molecular weight of CaCl2=40+35.5*2=111
Moles=weight in grams/Molecular weight
=13.7/111 = 0.1234 moles
Molarity = 0.1234 moles/750 ml.
=0.165 moles/l
Please check the atomic weights and the calculations.
Answered by
Dr Russ
Also note that units are missing and incorrect in places so that equations do not balance.
Relative Atomic Mass (RAM) of
Ca : 40
Cl : 35.5
Relative Molecular Mass of CaCl2=40+(35.5*2)=111
Moles=mass in grams/RAM
=13.7 g/111 g mol^-1
= 0.1234 mol
Molarity of solution = 0.1234 mol/0.7500 l.
=0.165 mol/l
or 0.165 M
Relative Atomic Mass (RAM) of
Ca : 40
Cl : 35.5
Relative Molecular Mass of CaCl2=40+(35.5*2)=111
Moles=mass in grams/RAM
=13.7 g/111 g mol^-1
= 0.1234 mol
Molarity of solution = 0.1234 mol/0.7500 l.
=0.165 mol/l
or 0.165 M
Answered by
MathMate
Thank you Dr. Russ.