Asked by keisha
x-2/3x+1,determine the inverse.
x= y-2/3y+1
x (3y+1)=y-2
3xy+x=y-2
(where do i go from here if i am going right)
x= y-2/3y+1
x (3y+1)=y-2
3xy+x=y-2
(where do i go from here if i am going right)
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