x-2/3x+1,determine the inverse.

x= y-2/3y+1
x (3y+1)=y-2
3xy+x=y-2
(where do i go from here if i am going right)

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the inverse of the function, we need to solve for y. Let's continue solving the equation:

3xy + x = y - 2

First, let's move all the terms involving y to one side of the equation:

3xy - y = -x - 2

Next, factor out the common y term:

y(3x - 1) = -x - 2

Finally, divide both sides of the equation by (3x - 1) to isolate y:

y = (-x - 2)/(3x - 1)

Therefore, the inverse of the function is:

f^-1(x) = (-x - 2)/(3x - 1)