To find the simplified polynomial in standard form when (2x-1)^2 is subtracted from 9x^2, we can expand (2x-1)^2 first.
Expanding (2x-1)^2, we get:
(2x-1)^2 = (2x-1)(2x-1)
Using the FOIL (First, Outer, Inner, Last) method, we multiply:
= 2x * 2x + 2x * (-1) + (-1) * 2x + (-1) * (-1)
= 4x^2 - 2x - 2x + 1
= 4x^2 - 4x + 1
Subtracting (2x-1)^2 from 9x^2, we have:
9x^2 - (4x^2 - 4x + 1)
Expanding the subtraction, we get:
9x^2 - 4x^2 + 4x - 1
Simplifying, we have:
(9x^2 - 4x^2) + 4x - 1
= 5x^2 + 4x - 1
Therefore, the result when (2x-1)^2 is subtracted from 9x^2 is 5x^2 + 4x - 1.
Writing as a simplified polynomial in standard form, what is the result when (2x-1)^2 is subtracted from 9x^2?
1 answer