Use the binomial theorem to expand the binomial. (s−3v)5 (1 point) Responses s5−5s4v+10s3v2−10s2v3+5sv4−v5 s to the 5th power minus 5 s to the 4th power v plus 10 s cubed v squared minus 10 s squared v cubed plus 5 s v to the 4th power minus v to the 5th power s5−15s4v+90s3v2−270s2v3+405sv4−243v5 s to the 5th power minus 15 s to the 4th power v plus 90 s cubed v squared minus 270 s squared v cubed plus 405 s v to the 4th power minus 243 v to the 5th power s5+15s4v+90s3v2+270s2v3+405sv4+243v5 s to the 5th power plus 15 s to the 4th power v plus 90 s cubed v squared plus 270 s squared v cubed plus 405 s v to the 4th power plus 243 v to the 5th power s5−15s4+90s3−270s2+405s−243
1 answer
The correct expansion is: s^5 - 15s^4v + 90s^3v^2 - 270s^2v^3 + 405sv^4 - 243v^5