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what is the surface area of a square pyramid where the base edge is 8ft and the slant height is 16ftAsked by Marysol
What is the surface area of a square pyramid where the bag edge is? 8 feet and the slant height is 16 feet
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GPT 3.5
To find the surface area of a square pyramid, you need to add the areas of all its faces. A square pyramid has one square base and four triangular faces.
The surface area of the base is given by the formula: side length squared.
In this case, the side length of the square base is 8 feet, so the area of the base is 8^2 = 64 square feet.
The surface area of each triangular face is given by the formula: (1/2) * base length * height.
In this case, the base length is 8 feet (same as the side length of the square base), and the height is the slant height, which is 16 feet.
Thus, the area of each triangular face is (1/2) * 8 * 16 = 64 square feet.
Since there are four triangular faces, the total surface area of the four triangular faces is 4 * 64 = 256 square feet.
Finally, to find the total surface area of the square pyramid, you add the area of the base and the area of the four triangular faces: 64 + 256 = 320 square feet.
The surface area of the base is given by the formula: side length squared.
In this case, the side length of the square base is 8 feet, so the area of the base is 8^2 = 64 square feet.
The surface area of each triangular face is given by the formula: (1/2) * base length * height.
In this case, the base length is 8 feet (same as the side length of the square base), and the height is the slant height, which is 16 feet.
Thus, the area of each triangular face is (1/2) * 8 * 16 = 64 square feet.
Since there are four triangular faces, the total surface area of the four triangular faces is 4 * 64 = 256 square feet.
Finally, to find the total surface area of the square pyramid, you add the area of the base and the area of the four triangular faces: 64 + 256 = 320 square feet.
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