Asked by Russell
if you have 19.2 x 10 ^ 20 over 4.8 x 10 ^ 9
Would you first subtract 4.8 from 19.2 then subtract 10 ^ 9 from 10 ^20
Leaving an answer of
14.4 x 10^11????
you are using the word "over", which implies division.
Why would you even consider subraction
(19.2 x 10 ^ 20) over (4.8 x 10 ^ 9)
=(19.2 x 10 ^ 20) รท (4.8 x 10 ^ 9)
= 19.2/4.8 * 10^20 / 10^9
= 4 * 10^11
Perhaps you were thinking of the procedure of dividing powers with the same base, where you <b>subtract</b> the exponents.
Thank you!!!! My mind is going blah.......first you divide number but then you just subtract then when you divide......this can be confusing, but I get it now :)
Thank you again!
Would you first subtract 4.8 from 19.2 then subtract 10 ^ 9 from 10 ^20
Leaving an answer of
14.4 x 10^11????
you are using the word "over", which implies division.
Why would you even consider subraction
(19.2 x 10 ^ 20) over (4.8 x 10 ^ 9)
=(19.2 x 10 ^ 20) รท (4.8 x 10 ^ 9)
= 19.2/4.8 * 10^20 / 10^9
= 4 * 10^11
Perhaps you were thinking of the procedure of dividing powers with the same base, where you <b>subtract</b> the exponents.
Thank you!!!! My mind is going blah.......first you divide number but then you just subtract then when you divide......this can be confusing, but I get it now :)
Thank you again!