Asked by Gille
How do I calculate how much sodium bicarbonate I need to neutralise 1L of 18M sulphuric acid?
Answers
Answered by
DrBob222
Write the balanced equation.
2NaHCO3 + H2SO4 ==>2H2O + 2CO2 + Na2SO4
Convert 1 L 18M H2SO4 to moles. M x L = moles.
Using the coefficients in the balanced equation, convert moles H2SO4 to moles NaHCO3.
Finally, convert moles NaHCO3 to grams.
grams = moles x molar mass.
Post your work if you get stuck.
2NaHCO3 + H2SO4 ==>2H2O + 2CO2 + Na2SO4
Convert 1 L 18M H2SO4 to moles. M x L = moles.
Using the coefficients in the balanced equation, convert moles H2SO4 to moles NaHCO3.
Finally, convert moles NaHCO3 to grams.
grams = moles x molar mass.
Post your work if you get stuck.
Answered by
Gille
Hi Dr Bob
Thanks for getting back but unfortunatley I am completely lost on this! Can you give me the figures please before I go nuts!!
Thanks G
Thanks for getting back but unfortunatley I am completely lost on this! Can you give me the figures please before I go nuts!!
Thanks G
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