Asked by maryk
I need to write an equation of the line containing the given point and parallel to the given line in y=mx+b form (7,9);x+4y=7......can you please help me find the solution
Answers
Answered by
Reiny
easiest way:
since the two lines are parallel, they will differ only in the constant.
so let the new line by x + 4y = k
but (7,9) lies on it
so 7 + 4(9) = k
k = 43 for an equation of x + 4y = 43
change to y = mx + b form
4y = -x + 43
y = (1/4)x + 43/4
since the two lines are parallel, they will differ only in the constant.
so let the new line by x + 4y = k
but (7,9) lies on it
so 7 + 4(9) = k
k = 43 for an equation of x + 4y = 43
change to y = mx + b form
4y = -x + 43
y = (1/4)x + 43/4
Answered by
Anonymous
On three consecutives passes, a football team gains 7 yards, loses 19 yards, and gains 38 yards. What number represents the total net yardage?
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