To find the equation of a line that is perpendicular to y = 5x – 7, we need to find the negative reciprocal of the slope of the given line.
The given line has a slope of 5, so the negative reciprocal of 5 is -1/5.
Therefore, the equation of the perpendicular line passing through (-10, 3) is:
y = (-1/5)x + b
To find the value of b, substitute the coordinates of the given point (-10, 3) into the equation:
3 = (-1/5)(-10) + b
3 = 2 + b
b = 3 - 2
b = 1
Therefore, the equation of the line that is perpendicular to y = 5x – 7 and passes through(-10, 3) is:
y = (-1/5)x + 1
So, the correct equation is:
y = -one fifthx + 1
Which equation is the equation of a line that passes through (–10, 3) and is perpendicular to y = 5x – 7?
(1 point)
Responses
y = 5x + 53
y = 5 x + 53
y = –one fifthx – 7
y = – Image with alt text: one fifth x – 7
y = –one fifthx + 1
y = – Image with alt text: one fifth x + 1
y = one fifthx + 5
1 answer
1 answer