A group of friends wants to go to the amusement park. They have no more than $110 to spend on parking and admission. Parking is $10.50, and tickets cost $23.50 per person, including tax. What is the maximum number of people who can go to the amusement park?

Answer 1

Let's call the number of people who can go to the amusement park x.
The cost of parking for x people would be 10.50*x.
The cost of tickets for x people would be 23.50*x.
We know that the total cost of parking and tickets cannot exceed $110, so we can write the following inequality:
10.50*x + 23.50*x ≤ 110
Combining like terms, we get:
34*x ≤ 110
Dividing both sides of the inequality by 34, we find:
x ≤ 110/34
x ≤ 3.235
Since we can't have a fraction of a person, we round down to the nearest whole number.
Therefore, the maximum number of people who can go to the amusement park is 3. Answer: \boxed{3}.

Answer 2

that answer wasnt right please give a new answer

Answer 3

I apologize for the mistake. Let's try again.

Let's call the number of people who can go to the amusement park x.
The cost of parking for x people would be $10.50.
The cost of tickets for x people would be $23.50*x.
We know that the total cost of parking and tickets cannot exceed $110, so we can write the following inequality:
10.50 + 23.50*x ≤ 110
Combining like terms, we get:
23.50*x ≤ 110 - 10.50
23.50*x ≤ 99.50
Dividing both sides of the inequality by 23.50, we find:
x ≤ 99.50/23.50
x ≤ 4.255
Since we can't have a fraction of a person, we round down to the nearest whole number.
Therefore, the maximum number of people who can go to the amusement park is 4. Answer: \boxed{4}.