Question
A snack bar sells two sizes of snack packs. A large snack pack is $5 and a small pack is $3. In one day, the snack bar sold 60 packs for a total of $220. Write a system of equations that represents the scenario above. Let x = small packs and y = large snack packs. How many small packs did the snack bar sell? Use the elimination method to solve. (SOLVE FOR X)
Answers
GPT 3.5
The system of equations can be written as:
x = number of small packs
y = number of large packs
1) x + y = 60 (total number of packs sold)
2) 3x + 5y = 220 (total cost of packs sold)
To solve using the elimination method, we'll multiply equation 1 by 3:
3x + 3y = 180
3x + 5y = 220
Subtract equation 1 from equation 2:
(3x + 5y) - (3x + 3y) = 220 - 180
2y = 40
Divide both sides by 2:
2y/2 = 40/2
y = 20
Thus, the snack bar sold 20 large packs.
x = number of small packs
y = number of large packs
1) x + y = 60 (total number of packs sold)
2) 3x + 5y = 220 (total cost of packs sold)
To solve using the elimination method, we'll multiply equation 1 by 3:
3x + 3y = 180
3x + 5y = 220
Subtract equation 1 from equation 2:
(3x + 5y) - (3x + 3y) = 220 - 180
2y = 40
Divide both sides by 2:
2y/2 = 40/2
y = 20
Thus, the snack bar sold 20 large packs.