Asked by Jeana
f(x+1)=8x^2+x-3
f(-x)=8x^2+x-3
work:
#1 8(x+1)(x+1)+x-3 then FOIL
8(x^2+x+x+2)+x-3
8x^2+16x+16+x-3
*8x^2+17x+13
#2 8(-x)^2-x-3
8x-x-3
*7x-3
I know on the first one you FOIL but im still getting it wrong?? The second one i thought was simple but im getting it wrong
f(-x)=8x^2+x-3
work:
#1 8(x+1)(x+1)+x-3 then FOIL
8(x^2+x+x+2)+x-3
8x^2+16x+16+x-3
*8x^2+17x+13
#2 8(-x)^2-x-3
8x-x-3
*7x-3
I know on the first one you FOIL but im still getting it wrong?? The second one i thought was simple but im getting it wrong
Answers
Answered by
bobpursley
#1 8(x+1)(x+1)+x-3 then FOIL
8(x^2+x+x+2)+x-3 ****Nope, lots of errors, so here is what it should be..
8(x^2+x+x+<b>1</b>)+ <b>(x+1)</b>-3
2)8(-x)^2 + (-x) -3
8x^2-x-3
8(x^2+x+x+2)+x-3 ****Nope, lots of errors, so here is what it should be..
8(x^2+x+x+<b>1</b>)+ <b>(x+1)</b>-3
2)8(-x)^2 + (-x) -3
8x^2-x-3
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