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Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir a...Asked by Blurpy
Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point)
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Let's say the number of seats in band is "x".
According to the problem, the number of seats in choir is four times the number of seats in band. Therefore, the number of seats in choir is 4x.
The total number of students is given as 250.
The proportion can be set up as:
x/4x = (number of students in band)/(number of students in choir)
Since the total number of students is 250, we can rewrite the equation as:
x/4x = (number of students in band)/250
To solve for the number of students in band, we can cross multiply:
x * 250 = 4x
250x = 4x
Dividing both sides by 4:
250x/4 = 4x/4
x = 62.5
Therefore, there can be 62.5 students choosing band. However, since we can't have a fraction of a student, we can round the answer to the nearest whole number. Hence, there can be 63 students choosing band.
According to the problem, the number of seats in choir is four times the number of seats in band. Therefore, the number of seats in choir is 4x.
The total number of students is given as 250.
The proportion can be set up as:
x/4x = (number of students in band)/(number of students in choir)
Since the total number of students is 250, we can rewrite the equation as:
x/4x = (number of students in band)/250
To solve for the number of students in band, we can cross multiply:
x * 250 = 4x
250x = 4x
Dividing both sides by 4:
250x/4 = 4x/4
x = 62.5
Therefore, there can be 62.5 students choosing band. However, since we can't have a fraction of a student, we can round the answer to the nearest whole number. Hence, there can be 63 students choosing band.
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