Question
What Mass Of H2O Is Produced If 25g NH3 React With 4Mol Oxygen
Answers
GPT 3.5
To determine the mass of water produced when 25g of NH3 reacts with 4 mol of oxygen, we need to calculate the amount of water produced first.
1) Write and balance the chemical equation:
4 NH3 + 5 O2 → 4 NO + 6 H2O
2) Convert the mass of NH3 to moles of NH3:
Given mass of NH3 = 25 g
Molar mass of NH3 = 17.03 g/mol
Moles of NH3 = (25 g) / (17.03 g/mol) = 1.468 mol
3) Determine the limiting reactant by comparing the stoichiometric ratios. The limiting reactant is the one that will be fully consumed in the reaction. From the balanced equation, we can see that the stoichiometric ratio between NH3 and O2 is 4:5. Thus, the reaction will require (5/4) * 1.468 mol = 1.835 mol of O2.
4) Calculate the amount of water produced based on the limiting reactant:
From the balanced equation, we can see that the stoichiometric ratio between O2 and H2O is 5:6. Thus, the amount of water produced will be (6/5) * 1.835 mol = 2.202 mol.
5) Convert moles of water to mass of water:
Molar mass of H2O = 18.015 g/mol
Mass of water = (2.202 mol) * (18.015 g/mol) = 39.3 g
Therefore, 39.3 grams of water will be produced when 25 grams of NH3 reacts with 4 mol of oxygen.
1) Write and balance the chemical equation:
4 NH3 + 5 O2 → 4 NO + 6 H2O
2) Convert the mass of NH3 to moles of NH3:
Given mass of NH3 = 25 g
Molar mass of NH3 = 17.03 g/mol
Moles of NH3 = (25 g) / (17.03 g/mol) = 1.468 mol
3) Determine the limiting reactant by comparing the stoichiometric ratios. The limiting reactant is the one that will be fully consumed in the reaction. From the balanced equation, we can see that the stoichiometric ratio between NH3 and O2 is 4:5. Thus, the reaction will require (5/4) * 1.468 mol = 1.835 mol of O2.
4) Calculate the amount of water produced based on the limiting reactant:
From the balanced equation, we can see that the stoichiometric ratio between O2 and H2O is 5:6. Thus, the amount of water produced will be (6/5) * 1.835 mol = 2.202 mol.
5) Convert moles of water to mass of water:
Molar mass of H2O = 18.015 g/mol
Mass of water = (2.202 mol) * (18.015 g/mol) = 39.3 g
Therefore, 39.3 grams of water will be produced when 25 grams of NH3 reacts with 4 mol of oxygen.