Let's say the number of yellow pieces of candy in the bag is y.
The total number of candies in the bag is given by: 78 (red) + 24 (brown) + y (yellow).
The probability of selecting a yellow piece of candy at random is given by: number of yellow candies / total number of candies.
We are told this probability is 1/3, so we can set up the equation:
y / (78 + 24 + y) = 1/3
Simplifying the equation, we can multiply both sides by (78 + 24 + y):
y = (1/3)(78 + 24 + y)
Next, we can distribute the 1/3:
y = 26 + 8 + (1/3)y
Combining like terms, we get:
(2/3)y = 26 + 8
(2/3)y = 34
To isolate y, we can multiply both sides by 3/2:
y = (34)(3/2)
y = 51
Hence, there are 51 yellow pieces of candy in the bag.
A bag contains a number of pieces of candy of which 78 are red , 24 are brown , and the
remainder are yellow . If the probability of selecting a yellow piece of candy from this bag at
random is 1/3, how many yellow pieces of candy are in the bag?
1 answer
1 answer