Asked by BOThelper
Aiden watered all the flowers at a business park. While watering, he noticed the daisies had been planted in groups of 8 and the lilies had been planted in groups of 4. If Aiden watered the same number of each flower, what is the minimum number of each that he must have watered?
[___]flowers
[___]flowers
Answers
Answered by
BOThelper
Debbie has 15 forks and 20 knives to place in silverware holders at the fast food restaurant where she works. She wants to distribute them equally, with no forks or knives left over. What is the greatest number of silverware holders Debbie can stock?
[___] silverware holders
[___] silverware holders
Answered by
GPT 3.5
To find the minimum number of each flower Aiden must have watered, we need to find the least common multiple (LCM) of 8 and 4.
The multiples of 8 are: 8, 16, 24, 32, 40, 48 ...
The multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 ...
From the lists, we can see that the LCM of 8 and 4 is 8.
Therefore, Aiden must have watered a minimum of 8 of each flower.
The multiples of 8 are: 8, 16, 24, 32, 40, 48 ...
The multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 ...
From the lists, we can see that the LCM of 8 and 4 is 8.
Therefore, Aiden must have watered a minimum of 8 of each flower.
Answered by
GPT 3.5
To find the greatest number of silverware holders Debbie can stock, we need to find the greatest common divisor (GCD) of 15 and 20.
The factors of 15 are: 1, 3, 5, 15.
The factors of 20 are: 1, 2, 4, 5, 10, 20.
The common factors of 15 and 20 are: 1 and 5.
Therefore, the greatest common divisor (GCD) of 15 and 20 is 5.
To distribute the forks and knives equally, Debbie can stock a maximum of 5 silverware holders.
The factors of 15 are: 1, 3, 5, 15.
The factors of 20 are: 1, 2, 4, 5, 10, 20.
The common factors of 15 and 20 are: 1 and 5.
Therefore, the greatest common divisor (GCD) of 15 and 20 is 5.
To distribute the forks and knives equally, Debbie can stock a maximum of 5 silverware holders.
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