The period of a sine function is given by the formula:
period = 2π / b
In this case, b = 2π0 = 0, so the period is undefined.
The amplitude of a sine function is the absolute value of the coefficient of sin(c(x-d)) in the function y = a sin(c(x-d)) + k. In this case, a = -6, so the amplitude is 6.
Since the period is undefined, the graph of y = -6 sin 2π0 will be a horizontal line passing through the y-axis at y = 0, with an amplitude of 6.
Here is a sketch of the function from 0 to 2π:
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6 -|
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0 2π
Find the period and amplitude of the following function. Then sketch the function from 0 to 2π.
y = -6 sin 2π0
1 answer