To calculate the total distance traveled, we need to find the distance covered during each phase of the car's motion and then sum them up.
Phase 1: Acceleration phase
Initial velocity, u = 0 m/s
Final velocity, v = 40 m/s
Time, t = 20 s
Using the equation of motion: v = u + at
40 = 0 + a * 20
a = 40/20
a = 2 m/s²
Using the equation of motion: s = ut + (1/2)at²
s = 0 * 20 + (1/2) * 2 * (20)²
s = 0 + 0.5 * 2 * 400
s = 0 + 0.5 * 800
s = 0 + 400
s = 400 m
Phase 2: Constant velocity phase
Velocity, v = 40 m/s
Time, t = 30 s
Since the velocity is constant, the distance covered is given by:
s = v * t
s = 40 * 30
s = 1200 m
Phase 3: Deceleration phase
Initial velocity, u = 40 m/s
Final velocity, v = 0 m/s
Time, t = 25 s
Using the equation of motion again: v = u + at
0 = 40 + a * 25
a = -40/25
a = -1.6 m/s²
Using the equation of motion: s = ut + (1/2)at²
s = 40 * 25 + (1/2) * (-1.6) * (25)²
s = 1000 - 20 * 25²
s = 1000 - 20 * 625
s = 1000 - 12500
s = -11500 m
Since distance cannot be negative, the distance covered during the deceleration phase is 0 m.
Now, we can calculate the total distance traveled:
Total distance = Phase 1 distance + Phase 2 distance + Phase 3 distance
Total distance = 400 m + 1200 m + 0 m
Total distance = 1600 m
Therefore, the car traveled a total distance of 1600 meters.
A car start from rest and affairs a velocity of 40m/s in 20s. If maintain this velocity for 30s and then comes to rest in 25s. Calculate the total distance travelled
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