For what value of a will 8x10 to the power of 3 be 40 times larger than ax10 to the power of 2?

1 answer

To solve this problem, we can set up an equation and then solve for "a".

Given that 8x10^3 is 40 times larger than ax10^2, we can write the equation as:

8x10^3 = 40(ax10^2)

We can simplify it further by canceling out the common factor of 10^2:

8x10^3 = 40ax10^2
8000 = 400ax

To solve for "a", we can divide both sides of the equation by 400x:

a = 8000 / (400x)

Therefore, the value of "a" that will make 8x10^3 be 40 times larger than ax10^2 is a = 8000 / (400x).