Subtract: (3b−2c)−(6c+2b)−(b+c) .(1 point)

Answer 1

(3b−2c)−(6c+2b)−(b+c)
= 3b - 2c - 6c - 2b - b - c
= (3b - 2b - 2b - b) + (-2c - 6c - c)
= -2b - 9c.