To determine the number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas, you can follow these steps:
Step 1: Write the balanced equation for the reaction:
N2 + 3H2 ==> 2NH3
Step 2: Convert the grams of H2 gas to moles. To do this, divide the given mass by the molar mass of H2.
mols = grams / molar mass
The molar mass of H2 is 2.016 g/mol.
mols H2 = 3.5 g / 2.016 g/mol
mols H2 = 1.734 mol (round to 3 significant figures)
Step 3: Use the coefficients from the balanced equation to convert moles of H2 to moles of NH3. From the balanced equation, the ratio of H2 to NH3 is 3:2.
mols NH3 = mols H2 * (2 mol NH3 / 3 mol H2)
mols NH3 = 1.734 mol * (2/3)
mols NH3 = 1.156 mol (round to 3 significant figures)
Step 4: Finally, convert moles of NH3 to grams of NH3. To do this, multiply the number of moles by the molar mass of NH3.
The molar mass of NH3 is 17.031 g/mol.
grams NH3 = mols NH3 * molar mass NH3
grams NH3 = 1.156 mol * 17.031 g/mol
grams NH3 ≈ 19.7 g (rounded to 3 significant figures)
Therefore, approximately 19.7 grams of NH3 will be produced by the reaction of 3.5 grams of hydrogen gas.