h=-16t^2+38t
3 answers
The equation is a quadratic equation in the form of h = -16t^2 + 38t.
Solve
To solve the equation h = -16t^2 + 38t, we can set the equation equal to zero and then factor it or use the quadratic formula.
Setting h = -16t^2 + 38t equal to zero, we have:
-16t^2 + 38t = 0
Now, we can factor out a common factor of 2t:
2t(-8t + 19) = 0
This equation is true if either 2t = 0 or -8t + 19 = 0.
Solving 2t = 0, we find that t = 0.
And solving -8t + 19 = 0, we find that t = 19/8.
Therefore, the solutions are t = 0 and t = 19/8.
Setting h = -16t^2 + 38t equal to zero, we have:
-16t^2 + 38t = 0
Now, we can factor out a common factor of 2t:
2t(-8t + 19) = 0
This equation is true if either 2t = 0 or -8t + 19 = 0.
Solving 2t = 0, we find that t = 0.
And solving -8t + 19 = 0, we find that t = 19/8.
Therefore, the solutions are t = 0 and t = 19/8.