This equation represents the height, h, of an object thrown into the air with an initial velocity of 60 feet per second. The equation is a quadratic equation in the form of h = at^2 + bt + c. The value of h represents the height of the object at time t.
In this equation, a = -16, b = 60, and c = 0. The term -16t^2 represents the effect of gravity, where the object undergoes acceleration due to gravity. The term 60t represents the effect of the initial velocity of the object, which causes it to move upwards. Finally, the term 0 represents the initial height of the object, which in this case is zero.
By plugging in different values of t into the equation, you can find the height of the object at a specific time. For example, if you plug in t = 1, the equation becomes h = -16(1)^2 + 60(1) + 0 = -16 + 60 + 0 = 44. So, the height of the object at time t = 1 second is 44 feet.
You can also use this equation to find the time it takes for the object to reach a certain height. For example, if you want to find the time it takes for the object to reach a height of 100 feet, you can set the equation equal to 100 and solve for t:
-16t^2 + 60t + 0 = 100
-16t^2 + 60t - 100 = 0
By solving this quadratic equation, you can find the values of t at which the object reaches a height of 100 feet.
h = -16t^2 + 60t +0
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