To find the first five terms of the sequence, we can substitute the values for n starting with n = 1 and calculate each term.
For n = 1:
a1 = 65(1) + 80 = 65 + 80 = 145
For n = 2:
a2 = 65(2) + 80 = 130 + 80 = 210
For n = 3:
a3 = 65(3) + 80 = 195 + 80 = 275
For n = 4:
a4 = 65(4) + 80 = 260 + 80 = 340
For n = 5:
a5 = 65(5) + 80 = 325 + 80 = 405
Therefore, the first five terms of the sequence defined by an = 65n + 80 are:
145, 210, 275, 340, 405.
Find the first five terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.
an = 65n + 80
5 answers
Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.
an = 10(10)n
an = 10(10)n
To find the first four terms of the sequence, we can substitute the values for n starting with n = 1 and calculate each term.
For n = 1:
a1 = 10(10)(1) = 10(10) = 100
For n = 2:
a2 = 10(10)(2) = 10(20) = 200
For n = 3:
a3 = 10(10)(3) = 10(30) = 300
For n = 4:
a4 = 10(10)(4) = 10(40) = 400
Therefore, the first four terms of the sequence defined by an = 10(10)n are:
100, 200, 300, 400.
For n = 1:
a1 = 10(10)(1) = 10(10) = 100
For n = 2:
a2 = 10(10)(2) = 10(20) = 200
For n = 3:
a3 = 10(10)(3) = 10(30) = 300
For n = 4:
a4 = 10(10)(4) = 10(40) = 400
Therefore, the first four terms of the sequence defined by an = 10(10)n are:
100, 200, 300, 400.
Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.
an = 7n2 − n − 1
an = 7n2 − n − 1
To find the first four terms of the sequence, we can substitute the values for n starting with n = 1 and calculate each term.
For n = 1:
a1 = 7(1)^2 − 1(1) − 1 = 7 − 1 − 1 = 5
For n = 2:
a2 = 7(2)^2 − 2(2) − 1 = 28 − 4 − 1 = 23
For n = 3:
a3 = 7(3)^2 − 3(3) − 1 = 63 − 9 − 1 = 53
For n = 4:
a4 = 7(4)^2 − 4(4) − 1 = 112 − 16 − 1 = 95
Therefore, the first four terms of the sequence defined by an = 7n^2 − n − 1 are:
5, 23, 53, 95.
For n = 1:
a1 = 7(1)^2 − 1(1) − 1 = 7 − 1 − 1 = 5
For n = 2:
a2 = 7(2)^2 − 2(2) − 1 = 28 − 4 − 1 = 23
For n = 3:
a3 = 7(3)^2 − 3(3) − 1 = 63 − 9 − 1 = 53
For n = 4:
a4 = 7(4)^2 − 4(4) − 1 = 112 − 16 − 1 = 95
Therefore, the first four terms of the sequence defined by an = 7n^2 − n − 1 are:
5, 23, 53, 95.