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A 28 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to F...Asked by Stoichiometry
A 38 g sample of iron ore is treated as follows.
The iron in the sample is all converted by
a series of chemical reactions to Fe2O3. The
mass of Fe2O3 is measured to be 11.1 g. What
was the mass of iron in the sample of ore?
Answer in units of g
The iron in the sample is all converted by
a series of chemical reactions to Fe2O3. The
mass of Fe2O3 is measured to be 11.1 g. What
was the mass of iron in the sample of ore?
Answer in units of g
Answers
Answered by
DrBob222
Another stoichiometry problem BUT there is a short cut that saves a lot of time; however, the shortcut is not taught, to my knowledge, anymore.
Here is the short cut.
grams Fe in the ore = grams Fe2O3 x (2*atomic mass Fe/molar mass Fe2O3) = ?
Here is the short cut.
grams Fe in the ore = grams Fe2O3 x (2*atomic mass Fe/molar mass Fe2O3) = ?
Answered by
Anonymous
6.93755
Answered by
gggg
not quite sure how to do this how do i get an answer through this thing