To find the equation of the line passing through (-3,4) and (-6,3), we first need to calculate the slope of the line.
The slope of a line passing through two points (x₁,y₁) and (x₂,y₂) is given by the formula:
m = (y₂ - y₁) / (x₂ - x₁)
Using the given points:
m = (3 - 4) / (-6 - (-3))
= (-1) / (-6 + 3)
= (-1) / (-3)
= 1/3
Now that we have the slope, we can use the point-slope form of a line:
y - y₁ = m(x - x₁)
Using (-3,4) as (x₁, y₁):
y - 4 = (1/3)(x - (-3))
y - 4 = (1/3)(x + 3)
Multiplying both sides by 3:
3(y - 4) = x + 3
3y - 12 = x + 3
Rearranging the terms:
3y = x + 3 + 12
3y = x + 15
The equation of the line passing through the points (-3,4) and (-6,3) in slope-intercept form is y = (1/3)x + 5.
What is the equation of the line that passes through the points (−3,4)
and (−6,3)
? Write the answer in slope-intercept form.(1 point)
y=( )x+
2 answers
What is the slope of the linear function 10x+2y=6 ? Use any method of linear functions to solve.(1 point)